Proof.
Let \nu : X' \to X be the normalization of X, see Varieties, Sections 33.27 and 33.41. Since X is singular \nu is not an isomorphism. Then k' = H^0(X', \mathcal{O}_{X'}) is a finite extension of k (Varieties, Lemma 33.26.2). The short exact sequence
0 \to \mathcal{O}_ X \to \nu _*\mathcal{O}_{X'} \to \mathcal{Q} \to 0
and the fact that \mathcal{Q} is supported in finitely many closed points give us that
H^1(X', \mathcal{O}_{X'}) = 0, i.e., X' has genus 0 as a curve over k',
there is a short exact sequence 0 \to k \to k' \to H^0(X, \mathcal{Q}) \to 0.
In particular k'/k is a nontrivial extension.
Next, we consider what is often called the conductor ideal
\mathcal{I} = \mathop{\mathcal{H}\! \mathit{om}}\nolimits _{\mathcal{O}_ X}(\nu _*\mathcal{O}_{X'}, \mathcal{O}_ X)
This is a quasi-coherent \mathcal{O}_ X-module. We view \mathcal{I} as an ideal in \mathcal{O}_ X via the map \varphi \mapsto \varphi (1). Thus \mathcal{I}(U) is the set of f \in \mathcal{O}_ X(U) such that f \left(\nu _*\mathcal{O}_{X'}(U)\right) \subset \mathcal{O}_ X(U). In other words, the condition is that f annihilates \mathcal{Q}. In other words, there is a defining exact sequence
0 \to \mathcal{I} \to \mathcal{O}_ X \to \mathop{\mathcal{H}\! \mathit{om}}\nolimits _{\mathcal{O}_ X}(\mathcal{Q}, \mathcal{Q})
Let U \subset X be an affine open containing the support of \mathcal{Q}. Then V = \mathcal{Q}(U) = H^0(X, \mathcal{Q}) is a k-vector space of dimension n - 1. The image of \mathcal{O}_ X(U) \to \mathop{\mathrm{Hom}}\nolimits _ k(V, V) is a commutative subalgebra, hence has dimension \leq n - 1 over k (this is a property of commutative subalgebras of matrix algebras; details omitted). We conclude that we have a short exact sequence
0 \to \mathcal{I} \to \mathcal{O}_ X \to \mathcal{A} \to 0
where \text{Supp}(\mathcal{A}) = \text{Supp}(\mathcal{Q}) and \dim _ k H^0(X, \mathcal{A}) \leq n - 1. On the other hand, the description \mathcal{I} = \mathop{\mathcal{H}\! \mathit{om}}\nolimits _{\mathcal{O}_ X}(\nu _*\mathcal{O}_{X'}, \mathcal{O}_ X) provides \mathcal{I} with a \nu _*\mathcal{O}_{X'}-module structure such that the inclusion map \mathcal{I} \to \nu _*\mathcal{O}_{X'} is a \nu _*\mathcal{O}_{X'}-module map. We conclude that \mathcal{I} = \nu _*\mathcal{I}' for some quasi-coherent sheaf of ideals \mathcal{I}' \subset \mathcal{O}_{X'}, see Morphisms, Lemma 29.11.6. Define \mathcal{A}' as the cokernel:
0 \to \mathcal{I}' \to \mathcal{O}_{X'} \to \mathcal{A}' \to 0
Combining the exact sequences so far we obtain a short exact sequence 0 \to \mathcal{A} \to \nu _*\mathcal{A}' \to \mathcal{Q} \to 0. Using the estimate above, combined with \dim _ k H^0(X, \mathcal{Q}) = n - 1, gives
\dim _ k H^0(X', \mathcal{A}') = \dim _ k H^0(X, \mathcal{A}) + \dim _ k H^0(X, \mathcal{Q}) \leq 2 n - 2
However, since X' is a curve over k' we see that the left hand side is divisible by n (Varieties, Lemma 33.44.10). As \mathcal{A} and \mathcal{A}' cannot be zero, we conclude that \dim _ k H^0(X', \mathcal{A}') = n which means that \mathcal{I}' is the ideal sheaf of a k'-rational point x'. By Proposition 53.10.4 we find X' \cong \mathbf{P}^1_{k'}. Going back to the equalities above, we conclude that \dim _ k H^0(X, \mathcal{A}) = 1. This means that \mathcal{I} is the ideal sheaf of a k-rational point x. Then \mathcal{A} = \kappa (x) = k and \mathcal{A}' = \kappa (x') = k' as skyscraper sheaves. Comparing the exact sequences given above, this immediately implies the result on structure sheaves as stated in the lemma.
\square
Comments (5)
Comment #5779 by Jonas Ehrhard on
Comment #5782 by Johan on
Comment #7709 by Cristian D. Gonzalez-Aviles on
Comment #7712 by Stacks Project on
Comment #7724 by Cristian D. Gonzalez-Aviles on
There are also: