Lemma 108.5.1. The diagonal of \mathrm{Quot}_{\mathcal{F}/X/B} \to B is a closed immersion. If \mathcal{F} is of finite type, then the diagonal is a closed immersion of finite presentation.
Proof. Suppose we have a scheme T/B and two quotients \mathcal{F}_ T \to \mathcal{Q}_ i, i = 1, 2 corresponding to T-valued points of \mathrm{Quot}_{\mathcal{F}/X/B} over B. Denote \mathcal{K}_1 the kernel of the first one and set u : \mathcal{K}_1 \to \mathcal{Q}_2 the composition. By Flatness on Spaces, Lemma 77.8.6 there is a closed subspace of T such that T' \to T factors through it if and only if the pullback u_{T'} is zero. This proves the diagonal is a closed immersion. Moreover, if \mathcal{F} is of finite type, then \mathcal{K}_1 is of finite type (Modules on Sites, Lemma 18.24.1) and we see that the diagonal is of finite presentation by the same lemma. \square
Comments (0)