Processing math: 100%

The Stacks project

Lemma 106.12.3. With assumption and notation as in Lemma 106.12.2. Then f is a (uniform) categorical moduli space if and only if \phi is a (uniform) categorical quotient. Similarly for moduli spaces in a full subcategory.

Proof. It is immediate from the 1-to-1 correspondence established in Lemma 106.12.2 that f is a categorical moduli space if and only if \phi is a categorical quotient (Quotients of Groupoids, Definition 83.4.1). If Y' \to Y is a morphism, then U' = Y' \times _ Y U \to Y' \times _ Y \mathcal{X} = \mathcal{X}' is a surjective, flat, locally finitely presented morphism as a base change of U \to \mathcal{X} (Criteria for Representability, Lemma 97.17.1). And R' = Y' \times _ Y R is equal to U' \times _{\mathcal{X}'} U' by transitivity of fibre products. Hence \mathcal{X}' = [U'/R'], see Algebraic Stacks, Remark 94.16.3. Thus the base change of our situation to Y' is another situation as in the statement of the lemma. From this it immediately follows that f is a uniform categorical moduli space if and only if \phi is a uniform categorical quotient. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.