Lemma 106.12.3. With assumption and notation as in Lemma 106.12.2. Then f is a (uniform) categorical moduli space if and only if \phi is a (uniform) categorical quotient. Similarly for moduli spaces in a full subcategory.
Proof. It is immediate from the 1-to-1 correspondence established in Lemma 106.12.2 that f is a categorical moduli space if and only if \phi is a categorical quotient (Quotients of Groupoids, Definition 83.4.1). If Y' \to Y is a morphism, then U' = Y' \times _ Y U \to Y' \times _ Y \mathcal{X} = \mathcal{X}' is a surjective, flat, locally finitely presented morphism as a base change of U \to \mathcal{X} (Criteria for Representability, Lemma 97.17.1). And R' = Y' \times _ Y R is equal to U' \times _{\mathcal{X}'} U' by transitivity of fibre products. Hence \mathcal{X}' = [U'/R'], see Algebraic Stacks, Remark 94.16.3. Thus the base change of our situation to Y' is another situation as in the statement of the lemma. From this it immediately follows that f is a uniform categorical moduli space if and only if \phi is a uniform categorical quotient. \square
Comments (0)