Lemma 51.15.1. Let X be a Noetherian scheme. Let T \subset X be a subset stable under specialization. Let \mathcal{F} be a coherent \mathcal{O}_ X-module. Then there is a unique map \mathcal{F} \to \mathcal{F}' of coherent \mathcal{O}_ X-modules such that
\mathcal{F} \to \mathcal{F}' is surjective,
\mathcal{F}_ x \to \mathcal{F}'_ x is an isomorphism for x \not\in T,
\text{depth}_{\mathcal{O}_{X, x}}(\mathcal{F}'_ x) \geq 1 for x \in T.
If f : Y \to X is a flat morphism with Y Noetherian, then f^*\mathcal{F} \to f^*\mathcal{F}' is the corresponding quotient for f^{-1}(T) \subset Y and f^*\mathcal{F}.
Proof.
Condition (3) just means that \text{Ass}(\mathcal{F}') \cap T = \emptyset . Thus \mathcal{F} \to \mathcal{F}' is the quotient of \mathcal{F} by the subsheaf of sections whose support is contained in T. This proves uniqueness. The statement on pullbacks follows from Divisors, Lemma 31.3.1 and the uniqueness.
Existence of \mathcal{F} \to \mathcal{F}'. By the uniqueness it suffices to prove the existence and uniqueness locally on X; small detail omitted. Thus we may assume X = \mathop{\mathrm{Spec}}(A) is affine and \mathcal{F} is the coherent module associated to the finite A-module M. Set M' = M / H^0_ T(M) with H^0_ T(M) as in Section 51.5. Then M_\mathfrak p = M'_\mathfrak p for \mathfrak p \not\in T which proves (1). On the other hand, we have H^0_ T(M) = \mathop{\mathrm{colim}}\nolimits H^0_ Z(M) where Z runs over the closed subsets of X contained in T. Thus by Dualizing Complexes, Lemmas 47.11.6 we have H^0_ T(M') = 0, i.e., no associated prime of M' is in T. Therefore \text{depth}(M'_\mathfrak p) \geq 1 for \mathfrak p \in T.
\square
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