Lemma 47.26.2. Let \varphi : A \to B be a homomorphism of Noetherian rings. Assume
A \to B is syntomic and induces a surjective map on spectra, or
A \to B is a faithfully flat local complete intersection, or
A \to B is faithfully flat of finite type with Gorenstein fibres.
Then K \in D(A) is a dualizing complex for A if and only if K \otimes _ A^\mathbf {L} B is a dualizing complex for B.
Proof.
Observe that A \to B satisfies (1) if and only if A \to B satisfies (2) by More on Algebra, Lemma 15.33.5. Observe that in both (2) and (3) the relative dualzing complex \varphi ^!(A) = \omega _{B/A}^\bullet is an invertible object of D(B), see Lemmas 47.25.4 and 47.25.5. Moreover we have \varphi ^!(K) = K \otimes _ A^\mathbf {L} \omega _{B/A}^\bullet in both cases, see Lemma 47.24.10 for case (3). Thus \varphi ^!(K) is the same as K \otimes _ A^\mathbf {L} B up to tensoring with an invertible object of D(B). Hence \varphi ^!(K) is a dualizing complex for B if and only if K \otimes _ A^\mathbf {L} B is (as being a dualizing complex is local and invariant under shifts). Thus we see that if K is dualizing for A, then K \otimes _ A^\mathbf {L} B is dualizing for B by Lemma 47.24.3. To descend the property, see Lemma 47.26.1.
\square
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