Processing math: 100%

The Stacks project

Lemma 42.2.3. Let R be a ring. Suppose that we have a short exact sequence of 2-periodic complexes

0 \to (M_1, N_1, \varphi _1, \psi _1) \to (M_2, N_2, \varphi _2, \psi _2) \to (M_3, N_3, \varphi _3, \psi _3) \to 0

If two out of three have cohomology modules of finite length so does the third and we have

e_ R(M_2, N_2, \varphi _2, \psi _2) = e_ R(M_1, N_1, \varphi _1, \psi _1) + e_ R(M_3, N_3, \varphi _3, \psi _3).

Proof. We abbreviate A = (M_1, N_1, \varphi _1, \psi _1), B = (M_2, N_2, \varphi _2, \psi _2) and C = (M_3, N_3, \varphi _3, \psi _3). We have a long exact cohomology sequence

\ldots \to H^1(C) \to H^0(A) \to H^0(B) \to H^0(C) \to H^1(A) \to H^1(B) \to H^1(C) \to \ldots

This gives a finite exact sequence

0 \to I \to H^0(A) \to H^0(B) \to H^0(C) \to H^1(A) \to H^1(B) \to K \to 0

with 0 \to K \to H^1(C) \to I \to 0 a filtration. By additivity of the length function (Algebra, Lemma 10.52.3) we see the result. \square


Comments (0)

There are also:

  • 2 comment(s) on Section 42.2: Periodic complexes and Herbrand quotients

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.