Lemma 42.2.3. Let R be a ring. Suppose that we have a short exact sequence of 2-periodic complexes
If two out of three have cohomology modules of finite length so does the third and we have
Lemma 42.2.3. Let R be a ring. Suppose that we have a short exact sequence of 2-periodic complexes
If two out of three have cohomology modules of finite length so does the third and we have
Proof. We abbreviate A = (M_1, N_1, \varphi _1, \psi _1), B = (M_2, N_2, \varphi _2, \psi _2) and C = (M_3, N_3, \varphi _3, \psi _3). We have a long exact cohomology sequence
This gives a finite exact sequence
with 0 \to K \to H^1(C) \to I \to 0 a filtration. By additivity of the length function (Algebra, Lemma 10.52.3) we see the result. \square
Comments (0)
There are also: