Processing math: 100%

The Stacks project

Lemma 42.2.4. Let R be a ring. If (M, N, \varphi , \psi ) is a 2-periodic complex such that M, N have finite length, then e_ R(M, N, \varphi , \psi ) = \text{length}_ R(M) - \text{length}_ R(N). In particular, if (M, \varphi , \psi ) is a (2, 1)-periodic complex such that M has finite length, then e_ R(M, \varphi , \psi ) = 0.

Proof. Observe that on the category of 2-periodic complexes with M, N of finite length the quantity β€œ\text{length}_ R(M) - \text{length}_ R(N)” is additive in short exact sequences (precise statement left to the reader). Consider the short exact sequence

0 \to (M, \mathop{\mathrm{Im}}(\varphi ), \varphi , 0) \to (M, N, \varphi , \psi ) \to (0, N/\mathop{\mathrm{Im}}(\varphi ), 0, 0) \to 0

The initial remark combined with the additivity of Lemma 42.2.3 reduces us to the cases (a) M = 0 and (b) \varphi is surjective. We leave those cases to the reader. \square


Comments (2)

Comment #8258 by Runlei Xiao on

In Lemma 42.2.4. the should change to if not the following exact sequence in your proof will be not well-defined.

There are also:

  • 2 comment(s) on Section 42.2: Periodic complexes and Herbrand quotients

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.