Lemma 51.17.1. Let p be a prime number. Let (A, \mathfrak m, \kappa ) be a Noetherian local ring with p = 0 in A. Let M be a finite A-module such that M \otimes _{A, F} A \cong M. Then M is finite free.
Proof. Choose a presentation A^{\oplus m} \to A^{\oplus n} \to M which induces an isomorphism \kappa ^{\oplus n} \to M/\mathfrak m M. Let T = (a_{ij}) be the matrix of the map A^{\oplus m} \to A^{\oplus n}. Observe that a_{ij} \in \mathfrak m. Applying base change by F, using right exactness of base change, we get a presentation A^{\oplus m} \to A^{\oplus n} \to M where the matrix is T = (a_{ij}^ p). Thus we have a presentation with a_{ij} \in \mathfrak m^ p. Repeating this construction we find that for each e \geq 1 there exists a presentation with a_{ij} \in \mathfrak m^ e. This implies the fitting ideals (More on Algebra, Definition 15.8.3) \text{Fit}_ k(M) for k < n are contained in \bigcap _{e \geq 1} \mathfrak m^ e. Since this is zero by Krull's intersection theorem (Algebra, Lemma 10.51.4) we conclude that M is free of rank n by More on Algebra, Lemma 15.8.8. \square
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