Lemma 51.5.3. Let A be a Noetherian ring. Let T \subset \mathop{\mathrm{Spec}}(A) be a subset stable under specialization. For any object K of D(A) we have
H^ i(RH^0_ T(K)) = \mathop{\mathrm{colim}}\nolimits _{Z \subset T\text{ closed}} H^ i_ Z(K)
Proof. Let J^\bullet be a K-injective complex representing K. By definition RH^0_ T is represented by the complex
H^0_ T(J^\bullet ) = \mathop{\mathrm{colim}}\nolimits H^0_ Z(J^\bullet )
where the equality follows from our definition of H^0_ T. Since filtered colimits are exact the cohomology of this complex in degree i is \mathop{\mathrm{colim}}\nolimits H^ i(H^0_ Z(J^\bullet )) = \mathop{\mathrm{colim}}\nolimits H^ i_ Z(K) as desired. \square
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