Situation 52.16.1. Here A is a Noetherian ring and I \subset \mathfrak a \subset A are ideals. We set X = \mathop{\mathrm{Spec}}(A), Y = V(I) = \mathop{\mathrm{Spec}}(A/I), and Z = V(\mathfrak a) = \mathop{\mathrm{Spec}}(A/\mathfrak a). Furthermore U = X \setminus Z.
Comments (0)