Lemma 52.16.6. In Situation 52.16.1 let (\mathcal{F}_ n) be an object of \textit{Coh}(U, I\mathcal{O}_ U). Let A', I', \mathfrak a' be the I-adic completions of A, I, \mathfrak a. Set X' = \mathop{\mathrm{Spec}}(A') and U' = X' \setminus V(\mathfrak a'). The following are equivalent
(\mathcal{F}_ n) extends to X, and
the pullback of (\mathcal{F}_ n) to U' is the completion of a coherent \mathcal{O}_{U'}-module.
Proof.
Recall that A \to A' is a flat ring map which induces an isomorphism A/I \to A'/I'. See Algebra, Lemmas 10.97.2 and 10.97.4. Thus X' \to X is a flat morphism inducing an isomorphism Y' \to Y. Thus U' \to U is a flat morphism which induces an isomorphism U' \cap Y' \to U \cap Y. This implies that in the commutative diagram
\xymatrix{ \textit{Coh}(X', I\mathcal{O}_{X'}) \ar[r] & \textit{Coh}(U', I\mathcal{O}_{U'}) \\ \textit{Coh}(X, I\mathcal{O}_ X) \ar[u] \ar[r] & \textit{Coh}(U, I\mathcal{O}_ U) \ar[u] }
the vertical functors are equivalences. See Cohomology of Schemes, Lemma 30.23.10. The lemma follows formally from this and the results of Lemma 52.16.3.
\square
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