Lemma 31.5.12 (0EME)—The Stacks project

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Table of contents
Part 2: Schemes
Chapter 31: Divisors
Section 31.5: Weakly associated points
Lemma 31.5.12 (cite)

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Lemma 31.5.12. Let $X$ be a reduced scheme. Then the weakly associated points of $X$ are exactly the generic points of the irreducible components of $X$.

Proof. Follows from Algebra, Lemma 10.66.3. $\square$

Comments (2)

Comment #3774 by Laurent Moret-Bailly on November 05, 2018 at 04:51

Typo in statement: "point" should be "points".

Comment #3904 by Johan on January 22, 2019 at 10:55

Thanks and fixed here.

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