Processing math: 100%

The Stacks project

Lemma 37.75.1. Given a cartesian square

\xymatrix{ U \ar[d]_\pi & U' \ar[l]^ h \ar[d]^{\pi '} \\ V & V' \ar[l]_ g }

with \pi locally quasi-finite with finite fibres and a function w : U \to \mathbf{Z} we have (\int _\pi w) \circ g = \int _{\pi '} (w \circ h).

Proof. This follows immediately from the second description of \int _\pi w given above. To prove it from the definition, you use that if E/F is a finite extension of fields and F'/F is another field extension, then writing (E \otimes _ F F')_{red} = \prod E'_ i as a product of fields finite over F', we have

[E : F]_ s = \sum [E'_ i : F']_ s

To prove this equality pick an algebraically closed field extension \Omega /F' and observe that

\begin{align*} [E : F]_ s & = |\mathop{\mathrm{Mor}}\nolimits _ F(E, \Omega )| \\ & = |\mathop{\mathrm{Mor}}\nolimits _{F'}(E \otimes _ F F', \Omega )| \\ & = |\mathop{\mathrm{Mor}}\nolimits _{F'}((E \otimes _ F F')_{red}, \Omega )| \\ & = \sum |\mathop{\mathrm{Mor}}\nolimits _{F'}(E'_ i, \Omega )| \\ & = \sum [E'_ i : F']_ s \end{align*}

where we have used Fields, Lemma 9.14.8. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.