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The Stacks project

Lemma 81.14.2. Let S be a scheme. Let X be a quasi-compact and quasi-separated algebraic space over S. Let U \subset X be a quasi-compact open.

  1. If Z_1, Z_2 \subset X are closed subspaces of finite presentation such that Z_1 \cap Z_2 \cap U = \emptyset , then there exists a U-admissible blowing up X' \to X such that the strict transforms of Z_1 and Z_2 are disjoint.

  2. If T_1, T_2 \subset |U| are disjoint constructible closed subsets, then there is a U-admissible blowing up X' \to X such that the closures of T_1 and T_2 are disjoint.

Proof. Proof of (1). The assumption that Z_ i \to X is of finite presentation signifies that the quasi-coherent ideal sheaf \mathcal{I}_ i of Z_ i is of finite type, see Morphisms of Spaces, Lemma 67.28.12. Denote Z \subset X the closed subspace cut out by the product \mathcal{I}_1 \mathcal{I}_2. Observe that Z \cap U is the disjoint union of Z_1 \cap U and Z_2 \cap U. By Divisors on Spaces, Lemma 71.19.5 there is a U \cap Z-admissible blowup Z' \to Z such that the strict transforms of Z_1 and Z_2 are disjoint. Denote Y \subset Z the center of this blowing up. Then Y \to X is a closed immersion of finite presentation as the composition of Y \to Z and Z \to X (Divisors on Spaces, Definition 71.19.1 and Morphisms of Spaces, Lemma 67.28.2). Thus the blowing up X' \to X of Y is a U-admissible blowing up. By general properties of strict transforms, the strict transform of Z_1, Z_2 with respect to X' \to X is the same as the strict transform of Z_1, Z_2 with respect to Z' \to Z, see Divisors on Spaces, Lemma 71.18.3. Thus (1) is proved.

Proof of (2). By Limits of Spaces, Lemma 70.14.1 there exists a finite type quasi-coherent sheaf of ideals \mathcal{J}_ i \subset \mathcal{O}_ U such that T_ i = V(\mathcal{J}_ i) (set theoretically). By Limits of Spaces, Lemma 70.9.8 there exists a finite type quasi-coherent sheaf of ideals \mathcal{I}_ i \subset \mathcal{O}_ X whose restriction to U is \mathcal{J}_ i. Apply the result of part (1) to the closed subspaces Z_ i = V(\mathcal{I}_ i) to conclude. \square


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