Lemma 62.3.4. Let $f : X \to Y$ be a proper morphism of schemes. Then $f_! = f_*$.

Proof. Immediate from the construction of $f_!$. $\square$

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).