Lemma 10.72.10. Let R be a local Noetherian ring and M a finite R-module. For a prime ideal \mathfrak p \subset R we have \text{depth}(M_\mathfrak p) + \dim (R/\mathfrak p) \geq \text{depth}(M).
Proof. If M_\mathfrak p = 0, then \text{depth}(M_\mathfrak p) = \infty and the lemma holds. If \text{depth}(M) \leq \dim (R/\mathfrak p), then the lemma is true. If \text{depth}(M) > \dim (R/\mathfrak p), then \mathfrak p is not contained in any associated prime \mathfrak q of M by Lemma 10.72.9. Hence we can find an x \in \mathfrak p not contained in any associated prime of M by Lemma 10.15.2 and Lemma 10.63.5. Then x is a nonzerodivisor on M, see Lemma 10.63.9. Hence \text{depth}(M/xM) = \text{depth}(M) - 1 and \text{depth}(M_\mathfrak p / x M_\mathfrak p) = \text{depth}(M_\mathfrak p) - 1 provided M_\mathfrak p is nonzero, see Lemma 10.72.7. Thus we conclude by induction on \text{depth}(M). \square
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