Lemma 36.11.1. Let $X$ be a Noetherian scheme. Then the functor
is an equivalence.
Lemma 36.11.1. Let $X$ be a Noetherian scheme. Then the functor
is an equivalence.
Proof. Observe that $\textit{Coh}(\mathcal{O}_ X) \subset \mathit{QCoh}(\mathcal{O}_ X)$ is a Serre subcategory, see Homology, Definition 12.10.1 and Lemma 12.10.2 and Cohomology of Schemes, Lemmas 30.9.2 and 30.9.3. On the other hand, if $\mathcal{G} \to \mathcal{F}$ is a surjection from a quasi-coherent $\mathcal{O}_ X$-module to a coherent $\mathcal{O}_ X$-module, then there exists a coherent submodule $\mathcal{G}' \subset \mathcal{G}$ which surjects onto $\mathcal{F}$. Namely, we can write $\mathcal{G}$ as the filtered union of its coherent submodules by Properties, Lemma 28.22.3 and then one of these will do the job. Thus the lemma follows from Derived Categories, Lemma 13.17.4. $\square$
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