Remark 45.7.2. Let X be a smooth projective variety. We obtain maps
where the first arrow is as in axiom (B) and \Delta ^* is pullback along the diagonal morphism \Delta : X \to X \times X. The composition is the cup product as pullback is an algebra homomorphism and \text{pr}_ i \circ \Delta = \text{id}. On the other hand, given cycles \alpha , \beta on X the intersection product is defined by the formula
In other words, \alpha \cdot \beta is the pullback of the exterior product \alpha \times \beta on X \times X by the diagonal. Note also that \alpha \times \beta = \text{pr}_1^*\alpha \cdot \text{pr}_2^*\beta in \mathop{\mathrm{CH}}\nolimits ^*(X \times X) (we omit the proof). Hence, given axiom (C)(a), axiom (C)(c) is equivalent to the statement that \gamma is compatible with exterior product in the sense that \gamma (\alpha \times \beta ) is equal to \text{pr}_1^*\gamma (\alpha ) \cup \text{pr}_2^*\gamma (\beta ). This is how axiom (C)(c) is formulated in [Kleiman-cycles].
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