Lemma 48.17.2. In Situation 48.16.1 let
be a commutative diagram of \textit{FTS}_ S where j and j' are open immersions. Then j^* \circ f^! = g^! \circ (j')^* as functors D^+_\mathit{QCoh}(\mathcal{O}_ Y) \to D^+(\mathcal{O}_ U).
Lemma 48.17.2. In Situation 48.16.1 let
be a commutative diagram of \textit{FTS}_ S where j and j' are open immersions. Then j^* \circ f^! = g^! \circ (j')^* as functors D^+_\mathit{QCoh}(\mathcal{O}_ Y) \to D^+(\mathcal{O}_ U).
Proof. Let h = f \circ j = j' \circ g. By Lemma 48.16.3 we have h^! = j^! \circ f^! = g^! \circ (j')^!. By Lemma 48.17.1 we have j^! = j^* and (j')^! = (j')^*. \square
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