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The Stacks project

Remark 91.7.5. Let f : (X, \mathcal{O}_ X) \to (S, \mathcal{O}_ S) and \mathcal{G} be as in Lemma 91.7.4. Consider an extension 0 \to \mathcal{G} \to \mathcal{O}_{X'} \to \mathcal{O}_ X \to 0 as in the lemma. We can choose a sheaf of sets \mathcal{E} and a commutative diagram

\xymatrix{ \mathcal{E} \ar[d]_{\alpha '} \ar[rd]^\alpha \\ \mathcal{O}_{X'} \ar[r] & \mathcal{O}_ X }

such that f^{-1}\mathcal{O}_ S[\mathcal{E}] \to \mathcal{O}_ X is surjective with kernel \mathcal{J}. (For example you can take any sheaf of sets surjecting onto \mathcal{O}_{X'}.) Then

\mathop{N\! L}\nolimits _{X/S} \cong \mathop{N\! L}\nolimits (\alpha ) = \left( \mathcal{J}/\mathcal{J}^2 \longrightarrow \Omega _{f^{-1}\mathcal{O}_ S[\mathcal{E}]/f^{-1}\mathcal{O}_ S} \otimes _{f^{-1}\mathcal{O}_ S[\mathcal{E}]} \mathcal{O}_ X\right)

See Modules, Section 17.31 and in particular Lemma 17.31.2. Of course \alpha ' determines a map f^{-1}\mathcal{O}_ S[\mathcal{E}] \to \mathcal{O}_{X'} which in turn determines a map

\mathcal{J}/\mathcal{J}^2 \longrightarrow \mathcal{G}

which in turn determines the element of \mathop{\mathrm{Ext}}\nolimits ^1_{\mathcal{O}_ X}(\mathop{N\! L}\nolimits (\alpha ), \mathcal{G}) = \mathop{\mathrm{Ext}}\nolimits ^1_{\mathcal{O}_ X}(\mathop{N\! L}\nolimits _{X/S}, \mathcal{G}) corresponding to \mathcal{O}_{X'} by the bijection of the lemma.


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