Proof.
Let \kappa = \max (|A|, |B|, \aleph _0). Set |M^\bullet | = |\bigcup M^ i| and similarly for other complexes. With this notation we have
\max (\kappa , |\bigcup M_1^ i \cup \bigcup N_1^ i|) = \max (\kappa , |M_1^\bullet |, |M_2^\bullet |)
for the quantity used in the statement of the lemma. We are going to use this and other observations coming from arithmetic of cardinals without further mention.
First, let us show that there are plenty of “small” subcomplexes. For every pair of collections E = \{ E^ i\} and F = \{ F^ i\} of finite subsets E^ i \subset M^ i, i \in \mathbf{Z} and F^ i \subset N^ i, i \in \mathbf{Z} we can let
M_1^\bullet \subset M_1(E, F)^\bullet \subset M^\bullet \quad \text{and}\quad N_1^\bullet \subset N_1(E, F)^\bullet \subset N^\bullet
be the smallest subcomplexes of A and B-modules such that a(M_1(E, F)^\bullet ) \subset N_1(E, F)^\bullet and such that E^ i \subset M_1(E, F)^ i and F^ i \subset M_2(E, F)^ i. Then it is easy to see that
|M_1(E, F)^\bullet | \leq \max (\kappa , |M_1^\bullet |) \quad \text{and}\quad |M_2(E, F)^\bullet | \leq \max (\kappa , |M_2^\bullet |)
Details omitted. It is clear that we have
M^\bullet = \mathop{\mathrm{colim}}\nolimits _{(E, F)} M_1(E, F)^\bullet \quad \text{and}\quad N^\bullet = \mathop{\mathrm{colim}}\nolimits _{(E, F)} N_1(E, F)^\bullet
and the colimits are (termwise) filtered colimits.
There exists a resolution \ldots \to F^{-1} \to F^0 \to B by free A-modules F_ i with |F_ i| \leq \kappa (details omitted). The cohomology modules of M_1^\bullet \otimes _ A^\mathbf {L} B are computed by \text{Tot}(M_1^\bullet \otimes _ A F^\bullet ). It follows that |H^ i(M_1^\bullet \otimes _ A^\mathbf {L} B)| \leq \max (\kappa , |M_1^\bullet |).
Let i \in \mathbf{Z} and let \xi \in H^ i(M_1^\bullet \otimes _ A^\mathbf {L} B) be an element which maps to zero in H^ i(N_1^\bullet ). Then \xi maps to zero in H^ i(N^\bullet ) and hence \xi maps to zero in H^ i(M^\bullet \otimes _ A^\mathbf {L} B). Since derived tensor product commutes with filtered colimits, we can find finite collections E_\xi and F_\xi as above such that \xi maps to zero in H^ i(M_1(E_\xi , F_\xi )^\bullet \otimes _ A^\mathbf {L} B).
Let i \in \mathbf{Z} and let \eta \in H^ i(N_1^\bullet ). Then the image of \eta in H^ i(N^\bullet ) is in the image of H^ i(M^\bullet \otimes _ A^\mathbf {L} B) \to H^ i(N^\bullet ). Hence as before, we can find finite collections E_\eta and F_\eta as above such that \eta maps to an element of H^ i(N_1(E_\eta , F_\eta ) which is in the image of the map H^ i(M_1(E_\eta , F_\eta )^\bullet \otimes _ A^\mathbf {L} B) \to H^ i(N_1(E_\eta , F_\eta ).
Now we simply define
M_2^\bullet = \sum \nolimits _\xi M_1(E_\xi , F_\xi )^\bullet + \sum \nolimits _\eta M_1(E_\eta , F_\eta )^\bullet
where the sum is over \xi and \eta as in the previous two paragraphs and the sum is taken inside M^\bullet . Similarly we set
N_2^\bullet = \sum \nolimits _\xi N_1(E_\xi , F_\xi )^\bullet + \sum \nolimits _\eta N_1(E_\eta , F_\eta )^\bullet
where the sum is taken inside N^\bullet . By construction we will have properties (1) and (2) with these choices. The bound (3) also follows as the set of \xi and \eta has cardinality at most \max (\kappa , |M_1^\bullet |, |N_1^\bullet |).
\square
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