Processing math: 0%

The Stacks project

Remark 13.34.4. Let \mathcal{A} be an abelian category. Let K^\bullet be a complex of \mathcal{A}. Then \tau _{\geq -n}K^\bullet is an inverse system of complexes and which in particular determines an inverse system in D(\mathcal{A}). Let us assume that R\mathop{\mathrm{lim}}\nolimits \tau _{\geq -n}K^\bullet exists. Then the canonical maps c_ n : K^\bullet \to \tau _{\geq -n}K^\bullet are compatible with the transition maps of our inverse system. By the defining distinguished triangle of Definition 13.34.1 and Lemma 13.4.2 we conclude there exists a morphism

c : K^\bullet \longrightarrow R\mathop{\mathrm{lim}}\nolimits \tau _{\geq -n}K^\bullet

in D(\mathcal{A}) such that the composition of c with the projection R\mathop{\mathrm{lim}}\nolimits \tau _{\geq -n}K^\bullet \to \tau _{\geq -m}K^\bullet is equal to c_ m. Now the morphism c may not be unique, but we claim that whether or not c is an isomorphism is independent of the choice of c (and of our choice of the homotopy limit). Namely, for i \in \mathbf{Z} and for m > -i the composition

H^ i(K^\bullet ) \xrightarrow {H^ i(c)} H^ i(R\mathop{\mathrm{lim}}\nolimits \tau _{\geq -n}K^\bullet ) \to H^ i(\tau _{\geq -m}K^\bullet ) = H^ i(K^\bullet )

is the identity. Hence H^ i(c) is an isomorphism if and only if the second map is an isomorphism. This is independent of c and also independent of the choice of the homotopy limit (as any two choices are isomorphic).


Comments (0)

There are also:

  • 3 comment(s) on Section 13.34: Derived limits

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.