The Stacks project

Comments 1 to 20 out of 10318 in reverse chronological order.

\begin{equation*} \DeclareMathOperator\Coim{Coim} \DeclareMathOperator\Coker{Coker} \DeclareMathOperator\Ext{Ext} \DeclareMathOperator\Hom{Hom} \DeclareMathOperator\Im{Im} \DeclareMathOperator\Ker{Ker} \DeclareMathOperator\Mor{Mor} \DeclareMathOperator\Ob{Ob} \DeclareMathOperator\Sh{Sh} \DeclareMathOperator\SheafExt{\mathcal{E}\mathit{xt}} \DeclareMathOperator\SheafHom{\mathcal{H}\mathit{om}} \DeclareMathOperator\Spec{Spec} \newcommand\colim{\mathop{\mathrm{colim}}\nolimits} \newcommand\lim{\mathop{\mathrm{lim}}\nolimits} \newcommand\Qcoh{\mathit{Qcoh}} \newcommand\Sch{\mathit{Sch}} \newcommand\QCohstack{\mathcal{QC}\!\mathit{oh}} \newcommand\Cohstack{\mathcal{C}\!\mathit{oh}} \newcommand\Spacesstack{\mathcal{S}\!\mathit{paces}} \newcommand\Quotfunctor{\mathrm{Quot}} \newcommand\Hilbfunctor{\mathrm{Hilb}} \newcommand\Curvesstack{\mathcal{C}\!\mathit{urves}} \newcommand\Polarizedstack{\mathcal{P}\!\mathit{olarized}} \newcommand\Complexesstack{\mathcal{C}\!\mathit{omplexes}} \newcommand\Pic{\mathop{\mathrm{Pic}}\nolimits} \newcommand\Picardstack{\mathcal{P}\!\mathit{ic}} \newcommand\Picardfunctor{\mathrm{Pic}} \newcommand\Deformationcategory{\mathcal{D}\!\mathit{ef}} \end{equation*}

On left comment #11283 on Item 4

nice project, however i take the knowledge.


On Yue Chen left comment #11282 on Lemma 59.63.5 in Étale Cohomology

I think the F_p-dimension of mod p etale cohomology H^q is only not greater than the k-dimension of H^q(X, O_X), they are not always equal as stated in the proof.


On left comment #11281 on Section 14.32 in Simplicial Methods

Typo in second paragraph of Second proof. "The map ..." should be .


On left comment #11280 on Lemma 14.32.2 in Simplicial Methods

Typo in second paragraph of Second proof. "The map ..." should be .


On left comment #11279 on Lemma 31.14.5 in Divisors

The second sentence of Lemma 31.14.5 should be "Let be an effective Cartier divisor on ".


On Laurent Moret-Bailly left comment #11278 on Lemma 67.37.9 in Morphisms of Algebraic Spaces

I agree with Torsten, except I would write "largest open subspace" instead of "unique maximal open subspace".


On Torsten Wedhorn left comment #11277 on Lemma 67.37.9 in Morphisms of Algebraic Spaces

One could make the statement slightly more precise by saying that there exists a unique maximal open subspace such that ... Similarly, for the analogous statement for algebraic stacks (Tag 0DZR).


On left comment #11276 on Lemma 59.63.3 in Étale Cohomology

Two typos in the proof:

"The invertible sheaf is the restriction of to "

should be replaced by

"The invertible sheaf is the restriction of to ".


On left comment #11275 on Lemma 10.41.5 in Commutative Algebra

In the first proof, what are and ? I thought we had and ?


On Olivier Benoist left comment #11274 on Lemma 61.27.6 in Pro-étale Cohomology

You may want to say what is in the statement.


On left comment #11273 on Lemma 59.69.3 in Étale Cohomology

In the first line of the description of , should not be there and instead should be an isomorphism.


On Shubhankar left comment #11272 on Lemma 101.33.7 in Morphisms of Algebraic Stacks

This is a pleasant fact which is easy to have misconceptions about. If useful, then I would suggest the slogan 'Quotients by fppf group schemes are smooth over the base' or equivalent.


On left comment #11271 on Section 57.11 in Derived Categories of Varieties

Regarding the section title: I think it should be “full faithfulness,” rather than “fully faithfulness” (‘full’ is an adjective and it should accompany a noun, ‘fully’ is an adverb and it accompanies an adjective, and ‘faithfulness’ is a noun).


On david left comment #11270 on Section 10.33 in Commutative Algebra

Is it easier to just verify that is a closed immersion, and then use tag 01IN (3)?


On Thiago Solovera e Nery left comment #11269 on Example 5.8.10 in Topology

I don't think that the singletons are the irreducible components, since is itself irreducible.


On left comment #11268 on Remark 21.19.3 in Cohomology on Sites

@#9911: As explained in [GW, 21.129], this is [Lip, 3.7.2.i; Del, 2.1.3].

References

[GW]. Ulrich Görtz and Torsten Wedhorn. Algebraic geometry II: cohomology of schemes. With examples and exercises. Springer Stud. Math. – Master. Wiesbaden: Springer Spektrum, 2023

[Lip]. Joseph Lipman. Notes on derived functors and Grothendieck duality. In Foundations of Grothendieck duality for diagrams of schemes, volume 1960 of Lect. Notes Math. Berlin: Springer, 2009

[Del]. Pierre Deligne. “Cohomologie à supports propres”. In: Théorie de Topos et Cohomologie Étale des Schémas (SGA4). Vol. III, Exp. XVII. Lecture Notes in Math. 305. Springer, 1971, pp. 250–461


On thesnakefromthelemma left comment #11267 on Lemma 12.30.2 in Homological Algebra

Lemma 002K (lemma-functorial-colimit) is somewhat overkill here. Suggested proof (to get rid of the "omit"):

  1. Wait for material on Karoubi envelopes, in particular their (2-)universal property, to be added to Section 09SF (section-karoubian) (cf. Comment 8065).

  2. Observe, as a consequence of the aforementioned (2-)universal property, that if is fully faithful and is Karoubian, then a (finite) biproduct of objects in lies in iff each biproductand lies in . (This probably also belongs in Section 09SF (section-karoubian).)

  3. Observe that where is the functor mapping to the Abelian group of cones under with vertex .

  4. Conclude by that is a Karoubian fully faithful subcategory (implicitly using that Karoubianness is a self-dual notion) that is "representable" iff and are "representable", hence that exists iff and exist.

("Representable" is in scare quotes because it seems that representability/Yoneda aren't treated within Stacks separately in the -enriched setting. Of course, the relevant results/proofs are vritually the same as in the case of . As an expositional question I'm not sure what the most parsimonious way to navigate this is.)


On thesnakefromthelemma left comment #11266 on Lemma 4.14.8 in Categories

An underrated lemma imho. Below is a suggested "abstract abstract nonsense nonsense" style proof. I.e., rather than explicitly deal in "abstract nonsense" (the data of cocones etc.), we instead reduce the claim to symbol-pushing in (without invoking or any other -categorical notions explicitly).


Dependencies:

The following would ideally be included as definitions/lemmata in an earlier section, presumably Section 0013 (section-definition-categories).

  1. Given categories , , and , define the usual bifunctor and show the bifunctoriality of

  2. Given categories and , define the constant functor as on objects and morphisms respectively and show that for any functor and natural transformation for which the respective compositions are well-defined, (There are also formulae for composition on the other side, but they aren't relevant to what follows.)


Argument:

Given category and diagam , define the (covariant) functor as I.e., is the set of cocones under with vertex equipped with the corresponding functorial action by morphisms of realized as the set of natural transformations from to the constant functor at .

By the prior discussion in Section 002D (section-limits), is defined as the corepresenting object of (precisely) when the latter exists. Hence by (the formal dual of) Lemma 001P (lemma-yoneda), it suffices in the context of the current lemma to construct a natural transformation (note the implicit contravariance).

Indeed, the formula prescribes the components (the parametrizing implicit in the type of ) of such a natural transformation; naturality is given by the equation or equivalently that (for all ) where the latter follows purely symbolically from the interchange law and the relevant identity above.


Note/strenghtening:

As currently formulated, this lemma is prima facie "evil" in the sense that it constructs a morphism (distinguishable up to equality) in terms of a functor (distinguishable only up to isomorphism). The underlying phenomenon is that there is, given , a (strict) -category defined so that

  • the objects of are the pairs

  • the morphisms from to are the pairs

  • the morphisms from to are the pairs

and we will have turned out to have, via the above formula, in fact constructed a (strict) -functor where the codomain is a -category so all the -morphisms of (including the noninvertible ones!) are sent to equalities in .

The proof is just more symbol pushing: Given as above, we must show that or equivalently that (for all ) This follows from the equality in the hypothesis, the interchange law, and the equality where is the object of at whose component we're implicitly working.

(Of course, it doesn't make expository sense to invoke the language of -categories so early in the chapter just to state all this. But what can be said purely -categorically is that any two and related by an induce equal maps between colimits.)


Ps.:

The above discussion formally dualizes to the corresponding discussion concerning limits (possibly relevant to Stacks) and straightforwardly generalizes to account for weighted (co)limits (presumably outside the scope of Stacks). As always, I am happy to implement and submit the desired subset of the above as a patch/PR.


On Hyun Jong Kim left comment #11265 on Section 21.35 in Cohomology on Sites

Just as RHom is being defined, there seems to be a typo: "Then we set Then we set".


On thesnakefromthelemma left comment #11264 on Lemma 10.43.8 in Commutative Algebra

Re Comment #12259, the idea is presumably to take the multiplicative closure of the union.

One way to shore up the slight handwave at the end is to observe that given diagrams and natural transformation such that for all there exists a (multiplicative) subset such that the component is the (up to unique iso) localization of by , then the map is itself the (up to unique iso) localization of by (the multiplicative subset generated by) the union over of the image of under the relevant component of the universal cocone of .

This is (assuming I haven't made some mistake) not at all hard to show by straightforward universal property wrangling; at the moment I can't think of any cleverer argument.