Lemma 10.125.4. Let R \to S be a finite type ring map. Let \mathfrak q \subset S be a prime lying over \mathfrak p \subset R. If R \to S is quasi-finite at \mathfrak q, then \dim (S_{\mathfrak q}) \leq \dim (R_{\mathfrak p}).
Proof. If R_{\mathfrak p} is Noetherian (and hence S_{\mathfrak q} Noetherian since it is essentially of finite type over R_{\mathfrak p}) then this follows immediately from Lemma 10.112.6 and the definitions. In the general case, let S' be the integral closure of R_\mathfrak p in S_\mathfrak p. By Zariski's Main Theorem 10.123.12 we have S_{\mathfrak q} = S'_{\mathfrak q'} for some \mathfrak q' \subset S' lying over \mathfrak q. By Lemma 10.112.3 we have \dim (S') \leq \dim (R_\mathfrak p) and hence a fortiori \dim (S_\mathfrak q) = \dim (S'_{\mathfrak q'}) \leq \dim (R_\mathfrak p). \square
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