Lemma 14.26.8. Let $\mathcal{C}$ be a category with finite coproducts. Let $U$ be a simplicial object of $\mathcal{C}$. Consider the maps $e_1, e_0 : U \to U \times \Delta [1]$, and $\pi : U \times \Delta [1] \to U$, see Lemma 14.13.3.
We have $\pi \circ e_1 = \pi \circ e_0 = \text{id}_ U$, and
The morphisms $\text{id}_{U \times \Delta [1]}$, and $e_0 \circ \pi $ are homotopic.
The morphisms $\text{id}_{U \times \Delta [1]}$, and $e_1 \circ \pi $ are homotopic.
Proof. The first assertion is trivial. For the second, consider the map of simplicial sets $\Delta [1] \times \Delta [1] \longrightarrow \Delta [1]$ which in degree $n$ assigns to a pair $(\beta _1, \beta _2)$, $\beta _ i : [n] \to [1]$ the morphism $\beta : [n] \to [1]$ defined by the rule
It is a morphism of simplicial sets, because the action $\Delta [1](\varphi ) : \Delta [1]_ n \to \Delta [1]_ m$ of $\varphi : [m] \to [n]$ is by precomposing. Clearly, using notation from Section 14.26, we have $\beta = \beta _1$ if $\beta _2 = \alpha ^ n_0$ and $\beta = \alpha ^ n_{n + 1}$ if $\beta _2 = \alpha ^ n_{n + 1}$. This implies easily that the induced morphism
of Lemma 14.13.3 is a homotopy from $\text{id}_{U \times \Delta [1]}$ to $e_0 \circ \pi $. Similarly for $e_1 \circ \pi $ (use minimum instead of maximum). $\square$
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