The Stacks project

Lemma 15.55.8. Let $R$ be a ring. For every $R$-module $M$ the $R$-module $J(M)$ is injective.

Proof. Note that $J(M) \cong \prod _{\varphi \in M^\vee } R^\vee $ as an $R$-module. As the product of injective modules is injective, it suffices to show that $R^\vee $ is injective. For this we use that

\[ \mathop{\mathrm{Hom}}\nolimits _ R(N, R^\vee ) = \mathop{\mathrm{Hom}}\nolimits _ R(N, \mathop{\mathrm{Hom}}\nolimits _{\mathbf{Z}}(R, \mathbf{Q}/\mathbf{Z})) = N^\vee \]

and the fact that $(-)^\vee $ is an exact functor by Lemma 15.55.6. $\square$


Comments (2)

Comment #113 by Kiran Kedlaya on

In the first sentence, I think should be .

There are also:

  • 4 comment(s) on Section 15.55: Injective modules

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 01DC. Beware of the difference between the letter 'O' and the digit '0'.