Lemma 30.13.2. Let f : Y \to X be a morphism of schemes. Let \mathcal{F} be a quasi-coherent sheaf on Y. Let \mathcal{I} be a quasi-coherent sheaf of ideals on X. If the morphism f is affine then \mathcal{I}f_*\mathcal{F} = f_*(f^{-1}\mathcal{I}\mathcal{F}).
Proof. The notation means the following. Since f^{-1} is an exact functor we see that f^{-1}\mathcal{I} is a sheaf of ideals of f^{-1}\mathcal{O}_ X. Via the map f^\sharp : f^{-1}\mathcal{O}_ X \to \mathcal{O}_ Y this acts on \mathcal{F}. Then f^{-1}\mathcal{I}\mathcal{F} is the subsheaf generated by sums of local sections of the form as where a is a local section of f^{-1}\mathcal{I} and s is a local section of \mathcal{F}. It is a quasi-coherent \mathcal{O}_ Y-submodule of \mathcal{F} because it is also the image of a natural map f^*\mathcal{I} \otimes _{\mathcal{O}_ Y} \mathcal{F} \to \mathcal{F}.
Having said this the proof is straightforward. Namely, the question is local and hence we may assume X is affine. Since f is affine we see that Y is affine too. Thus we may write Y = \mathop{\mathrm{Spec}}(B), X = \mathop{\mathrm{Spec}}(A), \mathcal{F} = \widetilde{M}, and \mathcal{I} = \widetilde{I}. The assertion of the lemma in this case boils down to the statement that
where M_ A indicates the A-module associated to the B-module M. \square
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