Lemma 32.4.7. In Situation 32.4.5. Suppose that \mathcal{F}_0 is a quasi-coherent sheaf on S_0. Set \mathcal{F}_ i = f_{i0}^*\mathcal{F}_0 for i \geq 0 and set \mathcal{F} = f_0^*\mathcal{F}_0. Then
Proof. Write \mathcal{A}_ j = f_{i0, *} \mathcal{O}_{S_ i}. This is a quasi-coherent sheaf of \mathcal{O}_{S_0}-algebras (see Morphisms, Lemma 29.11.5) and S_ i is the relative spectrum of \mathcal{A}_ i over S_0. In the proof of Lemma 32.2.2 we constructed S as the relative spectrum of \mathcal{A} = \mathop{\mathrm{colim}}\nolimits _{i \geq 0} \mathcal{A}_ i over S_0. Set
and
Then we have f_{i0, *} \mathcal{F}_ i = \mathcal{M}_ i and f_{0, *}\mathcal{F} = \mathcal{M}. Since \mathcal{A} is the colimit of the sheaves \mathcal{A}_ i and since tensor product commutes with directed colimits, we conclude that \mathcal{M} = \mathop{\mathrm{colim}}\nolimits _{i \geq 0} \mathcal{M}_ i. Since S_0 is quasi-compact and quasi-separated we see that
see Sheaves, Lemma 6.29.1 and Topology, Lemma 5.27.1 for the middle equality. \square
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