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111.30 Filtered derived category

In order to do the exercises in this section, please read the material in Homology, Section 12.19. We will say A is a filtered object of \mathcal{A}, to mean that A comes endowed with a filtration F which we omit from the notation.

Exercise 111.30.1. Let \mathcal{A} be an abelian category. Let I be a filtered object of \mathcal{A}. Assume that the filtration on I is finite and that each \text{gr}^ p(I) is an injective object of \mathcal{A}. Show that there exists an isomorphism I \cong \bigoplus \text{gr}^ p(I) with filtration F^ p(I) corresponding to \bigoplus _{p' \geq p} \text{gr}^ p(I).

Exercise 111.30.2. Let \mathcal{A} be an abelian category. Let I be a filtered object of \mathcal{A}. Assume that the filtration on I is finite. Show the following are equivalent:

  1. For any solid diagram

    \xymatrix{ A \ar[r]_\alpha \ar[d] & B \ar@{-->}[ld] \\ I & }

    of filtered objects with (i) the filtrations on A and B are finite, and (ii) \text{gr}(\alpha ) injective the dotted arrow exists making the diagram commute.

  2. Each \text{gr}^ p I is injective.

Note that given a morphism \alpha : A \to B of filtered objects with finite filtrations to say that \text{gr}(\alpha ) injective is the same thing as saying that \alpha is a strict monomorphism in the category \text{Fil}(\mathcal{A}). Namely, being a monomorphism means \mathop{\mathrm{Ker}}(\alpha ) = 0 and strict means that this also implies \mathop{\mathrm{Ker}}(\text{gr}(\alpha )) = 0. See Homology, Lemma 12.19.13. (We only use the term “injective” for a morphism in an abelian category, although it makes sense in any additive category having kernels.) The exercises above justifies the following definition.

Definition 111.30.3. Let \mathcal{A} be an abelian category. Let I be a filtered object of \mathcal{A}. Assume the filtration on I is finite. We say I is filtered injective if each \text{gr}^ p(I) is an injective object of \mathcal{A}.

We make the following definition to avoid having to keep saying “with a finite filtration” everywhere.

Definition 111.30.4. Let \mathcal{A} be an abelian category. We denote \text{Fil}^ f(\mathcal{A}) the full subcategory of \text{Fil}(\mathcal{A}) whose objects consist of those A \in \mathop{\mathrm{Ob}}\nolimits (\text{Fil}(\mathcal{A})) whose filtration is finite.

Exercise 111.30.5. Let \mathcal{A} be an abelian category. Assume \mathcal{A} has enough injectives. Let A be an object of \text{Fil}^ f(\mathcal{A}). Show that there exists a strict monomorphism \alpha : A \to I of A into a filtered injective object I of \text{Fil}^ f(\mathcal{A}).

Definition 111.30.6. Let \mathcal{A} be an abelian category. Let \alpha : K^\bullet \to L^\bullet be a morphism of complexes of \text{Fil}(\mathcal{A}). We say that \alpha is a filtered quasi-isomorphism if for each p \in \mathbf{Z} the morphism \text{gr}^ p(K^\bullet ) \to \text{gr}^ p(L^\bullet ) is a quasi-isomorphism.

Definition 111.30.7. Let \mathcal{A} be an abelian category. Let K^\bullet be a complex of \text{Fil}^ f(\mathcal{A}). We say that K^\bullet is filtered acyclic if for each p \in \mathbf{Z} the complex \text{gr}^ p(K^\bullet ) is acyclic.

Exercise 111.30.8. Let \mathcal{A} be an abelian category. Let \alpha : K^\bullet \to L^\bullet be a morphism of bounded below complexes of \text{Fil}^ f(\mathcal{A}). (Note the superscript f.) Show that the following are equivalent:

  1. \alpha is a filtered quasi-isomorphism,

  2. for each p \in \mathbf{Z} the map \alpha : F^ pK^\bullet \to F^ pL^\bullet is a quasi-isomorphism,

  3. for each p \in \mathbf{Z} the map \alpha : K^\bullet /F^ pK^\bullet \to L^\bullet /F^ pL^\bullet is a quasi-isomorphism, and

  4. the cone of \alpha (see Derived Categories, Definition 13.9.1) is a filtered acyclic complex.

Moreover, show that if \alpha is a filtered quasi-isomorphism then \alpha is also a usual quasi-isomorphism.

Exercise 111.30.9. Let \mathcal{A} be an abelian category. Assume \mathcal{A} has enough injectives. Let A be an object of \text{Fil}^ f(\mathcal{A}). Show there exists a complex I^\bullet of \text{Fil}^ f(\mathcal{A}), and a morphism A[0] \to I^\bullet such that

  1. each I^ p is filtered injective,

  2. I^ p = 0 for p < 0, and

  3. A[0] \to I^\bullet is a filtered quasi-isomorphism.

Exercise 111.30.10. Let \mathcal{A} be an abelian category. Assume \mathcal{A} has enough injectives. Let K^\bullet be a bounded below complex of objects of \text{Fil}^ f(\mathcal{A}). Show there exists a filtered quasi-isomorphism \alpha : K^\bullet \to I^\bullet with I^\bullet a complex of \text{Fil}^ f(\mathcal{A}) having filtered injective terms I^ n, and bounded below. In fact, we may choose \alpha such that each \alpha ^ n is a strict monomorphism.

Exercise 111.30.11. Let \mathcal{A} be an abelian category. Consider a solid diagram

\xymatrix{ K^\bullet \ar[r]_\alpha \ar[d]_\gamma & L^\bullet \ar@{-->}[dl]^\beta \\ I^\bullet }

of complexes of \text{Fil}^ f(\mathcal{A}). Assume K^\bullet , L^\bullet and I^\bullet are bounded below and assume each I^ n is a filtered injective object. Also assume that \alpha is a filtered quasi-isomorphism.

  1. There exists a map of complexes \beta making the diagram commute up to homotopy.

  2. If \alpha is a strict monomorphism in every degree then we can find a \beta which makes the diagram commute.

Exercise 111.30.12. Let \mathcal{A} be an abelian category. Let K^\bullet , K^\bullet be complexes of \text{Fil}^ f(\mathcal{A}). Assume

  1. K^\bullet bounded below and filtered acyclic, and

  2. I^\bullet bounded below and consisting of filtered injective objects.

Then any morphism K^\bullet \to I^\bullet is homotopic to zero.

Exercise 111.30.13. Let \mathcal{A} be an abelian category. Consider a solid diagram

\xymatrix{ K^\bullet \ar[r]_\alpha \ar[d]_\gamma & L^\bullet \ar@{-->}[dl]^{\beta _ i} \\ I^\bullet }

of complexes of \text{Fil}^ f(\mathcal{A}). Assume K^\bullet , L^\bullet and I^\bullet bounded below and each I^ n a filtered injective object. Also assume \alpha a filtered quasi-isomorphism. Any two morphisms \beta _1, \beta _2 making the diagram commute up to homotopy are homotopic.


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