Lemma 10.124.1. Let A \subset B be an extension of domains. Assume
A is a local Noetherian ring of dimension 1,
A \to B is of finite type, and
the induced extension L/K of fraction fields is finite.
Then B is semi-local. Let x \in \mathfrak m_ A, x \not= 0. Let \mathfrak m_ i, i = 1, \ldots , n be the maximal ideals of B. Then
[L : K]\text{ord}_ A(x) \geq \sum \nolimits _ i [\kappa (\mathfrak m_ i) : \kappa (\mathfrak m_ A)] \text{ord}_{B_{\mathfrak m_ i}}(x)
where \text{ord} is defined as in Definition 10.121.2. We have equality if and only if A \to B is finite.
Proof.
The ring B is semi-local by Lemma 10.113.2. Let B' be the integral closure of A in B. By Lemma 10.123.14 we can find a finite A-subalgebra C \subset B' such that on setting \mathfrak n_ i = C \cap \mathfrak m_ i we have C_{\mathfrak n_ i} \cong B_{\mathfrak m_ i} and the primes \mathfrak n_1, \ldots , \mathfrak n_ n are pairwise distinct. The ring C is semi-local by Lemma 10.113.2. Let \mathfrak p_ j, j = 1, \ldots , m be the other maximal ideals of C (the “missing points”). By Lemma 10.121.8 we have
\text{ord}_ A(x^{[L : K]}) = \sum \nolimits _ i [\kappa (\mathfrak n_ i) : \kappa (\mathfrak m_ A)] \text{ord}_{C_{\mathfrak n_ i}}(x) + \sum \nolimits _ j [\kappa (\mathfrak p_ j) : \kappa (\mathfrak m_ A)] \text{ord}_{C_{\mathfrak p_ j}}(x)
hence the inequality follows. In case of equality we conclude that m = 0 (no “missing points”). Hence C \subset B is an inclusion of semi-local rings inducing a bijection on maximal ideals and an isomorphism on all localizations at maximal ideals. So if b \in B, then I = \{ x \in C \mid xb \in C\} is an ideal of C which is not contained in any of the maximal ideals of C, and hence I = C, hence b \in C. Thus B = C and B is finite over A.
\square
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