Lemma 29.44.8 (02NT)—The Stacks project

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Table of contents
Part 2: Schemes
Chapter 29: Morphisms of Schemes
Section 29.44: Integral and finite morphisms
Lemma 29.44.8 (cite)

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Lemma 29.44.8. Let $f : X \to S$ be an integral morphism. Then every point of $X$ is closed in its fibre.

Proof. See Algebra, Lemma 10.36.20. $\square$

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