Lemma 31.23.9. Let X be a scheme. Let \mathcal{L} be an invertible \mathcal{O}_ X-module. Let s be a regular meromorphic section of \mathcal{L}. Let us denote \mathcal{I} \subset \mathcal{O}_ X the sheaf of ideals defined by the rule
\mathcal{I}(V) = \{ f \in \mathcal{O}_ X(V) \mid fs \in \mathcal{L}(V)\} .
The formula makes sense since \mathcal{L}(V) \subset \mathcal{K}_ X(\mathcal{L})(V). Then \mathcal{I} is a quasi-coherent sheaf of ideals and we have injective maps
1 : \mathcal{I} \longrightarrow \mathcal{O}_ X, \quad s : \mathcal{I} \longrightarrow \mathcal{L}
whose cokernels are supported on closed nowhere dense subsets of X.
Proof.
The question is local on X. Hence we may assume that X = \mathop{\mathrm{Spec}}(A), and \mathcal{L} = \mathcal{O}_ X. After shrinking further we may assume that s = a/b with a, b \in A both nonzerodivisors in A. Set I = \{ x \in A \mid x(a/b) \in A\} .
To show that \mathcal{I} is quasi-coherent we have to show that I_ f = \{ x \in A_ f \mid x(a/b) \in A_ f\} for every f \in A. If c/f^ n \in A_ f, (c/f^ n)(a/b) \in A_ f, then we see that f^ mc(a/b) \in A for some m, hence c/f^ n \in I_ f. Conversely it is easy to see that I_ f is contained in \{ x \in A_ f \mid x(a/b) \in A_ f\} . This proves quasi-coherence.
Let us prove the final statement. It is clear that (b) \subset I. Hence V(I) \subset V(b) is a nowhere dense subset as b is a nonzerodivisor. Thus the cokernel of 1 is supported in a nowhere dense closed set. The same argument works for the cokernel of s since s(b) = (a) \subset sI \subset A.
\square
Comments (2)
Comment #3768 by Laurent Moret-Bailly on
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