Lemma 73.9.4. Let S be a scheme, and let X be an algebraic space over S. Suppose that \{ f_ i : X_ i \to X\} _{i \in I} is a family of morphisms of algebraic spaces with target X. Let U \to X be a surjective étale morphism from a scheme towards X. Then \{ f_ i : X_ i \to X\} _{i \in I} is an fpqc covering of X if and only if \{ U \times _ X X_ i \to U\} _{i \in I} is an fpqc covering of U.
Proof. If \{ X_ i \to X\} _{i \in I} is an fpqc covering, then so is \{ U \times _ X X_ i \to U\} _{i \in I} by Lemma 73.9.3. Assume that \{ U \times _ X X_ i \to U\} _{i \in I} is an fpqc covering. Let h : Z \to X be a morphism from an affine scheme towards X. Then we see that U \times _ X Z \to Z is a surjective étale morphism of schemes, in particular open. Hence we can find finitely many affine opens W_1, \ldots , W_ t of U \times _ X Z whose images cover Z. For each j we may apply the condition that \{ U \times _ X X_ i \to U\} _{i \in I} is an fpqc covering to the morphism W_ j \to U, and obtain a standard fpqc covering \{ W_{jl} \to W_ j\} which refines \{ W_ j \times _ X X_ i \to W_ j\} _{i \in I}. Hence \{ W_{jl} \to Z\} is a standard fpqc covering of Z (see Topologies, Lemma 34.9.11) which refines \{ Z \times _ X X_ i \to X\} and we win. \square
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