Theorem 58.67.1 (The Fundamental Exact Sequence). There is a short exact sequence of étale sheaves on $X$

## 58.67 Higher vanishing for the multiplicative group

In this section, we fix an algebraically closed field $k$ and a smooth curve $X$ over $k$. We denote $i_ x : x \hookrightarrow X$ the inclusion of a closed point of $X$ and $j : \eta \hookrightarrow X$ the inclusion of the generic point. We also denote $X_0$ the set of closed points of $X$.

**Proof.**
Let $\varphi : U \to X$ be an étale morphism. Then by properties of étale morphisms (Proposition 58.26.2), $U = \coprod _ i U_ i$ where each $U_ i$ is a smooth curve mapping to $X$. The above sequence for $U$ is a product of the corresponding sequences for each $U_ i$, so it suffices to treat the case where $U$ is connected, hence irreducible. In this case, there is a well known exact sequence

This amounts to a sequence

which, unfolding definitions, is nothing but a sequence

This defines the maps in the Fundamental Exact Sequence and shows it is exact except possibly at the last step. To see surjectivity, let us recall that if $U$ is a nonsingular curve and $D$ is a divisor on $U$, then there exists a Zariski open covering $\{ U_ j \to U\} $ of $U$ such that $D|_{U_ j} = \text{div}(f_ j)$ for some $f_ j \in k(U)^*$. $\square$

Lemma 58.67.2. For any $q \geq 1$, $R^ q j_*\mathbf{G}_{m, \eta } = 0$.

**Proof.**
We need to show that $(R^ q j_*\mathbf{G}_{m, \eta })_{\bar x} = 0$ for every geometric point $\bar x$ of $X$.

Assume that $\bar x$ lies over a closed point $x$ of $X$. Let $\mathop{\mathrm{Spec}}(A)$ be an affine open neighbourhood of $x$ in $X$, and $K$ the fraction field of $A$. Then

The ring $\mathcal{O}^{sh}_{X, \bar x} \otimes _ A K$ is a localization of the discrete valuation ring $\mathcal{O}^{sh}_{X, \bar x}$, so it is either $\mathcal{O}^{sh}_{X, \bar x}$ again, or its fraction field $K^{sh}_{\bar x}$. But since some local uniformizer gets inverted, it must be the latter. Hence

Now recall that $\mathcal{O}^{sh}_{X, \bar x} = \mathop{\mathrm{colim}}\nolimits _{(U, \bar u) \to \bar x} \mathcal{O}(U) = \mathop{\mathrm{colim}}\nolimits _{A \subset B} B$ where $A \to B$ is étale, hence $K^{sh}_{\bar x}$ is an algebraic extension of $K = k(X)$, and we may apply Lemma 58.66.12 to get the vanishing.

Assume that $\bar x = \bar\eta $ lies over the generic point $\eta $ of $X$ (in fact, this case is superfluous). Then $\mathcal{O}_{X, \bar\eta } = \kappa (\eta )^{sep}$ and thus

since the corresponding Galois group is trivial. $\square$

Lemma 58.67.3. For all $p \geq 1$, $H_{\acute{e}tale}^ p(X, j_*\mathbf{G}_{m, \eta }) = 0$.

**Proof.**
The Leray spectral sequence reads

which vanishes for $p+q \geq 1$ by Lemma 58.66.12. Taking $q = 0$, we get the desired vanishing. $\square$

Lemma 58.67.4. For all $q \geq 1$, $H_{\acute{e}tale}^ q(X, \bigoplus _{x \in X_0} {i_ x}_* \underline{\mathbf{Z}}) = 0$.

**Proof.**
For $X$ quasi-compact and quasi-separated, cohomology commutes with colimits, so it suffices to show the vanishing of $H_{\acute{e}tale}^ q(X, {i_ x}_* \underline{\mathbf{Z}})$. But then the inclusion $i_ x$ of a closed point is finite so $R^ p {i_ x}_* \underline{\mathbf{Z}} = 0$ for all $p \geq 1$ by Proposition 58.54.2. Applying the Leray spectral sequence, we see that $H_{\acute{e}tale}^ q(X, {i_ x}_* \underline{\mathbf{Z}}) = H_{\acute{e}tale}^ q(x, \underline{\mathbf{Z}})$. Finally, since $x$ is the spectrum of an algebraically closed field, all higher cohomology on $x$ vanishes.
$\square$

Concluding this series of lemmata, we get the following result.

Theorem 58.67.5. Let $X$ be a smooth curve over an algebraically closed field. Then

**Proof.**
See discussion above.
$\square$

We also get the cohomology long exact sequence

although this is the familiar

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