Lemma 4.35.3. Let \mathcal{C} be a category. Let p : \mathcal{S} \to \mathcal{C} be a fibred category. Let \mathcal{S}' be the subcategory of \mathcal{S} defined as follows
\mathop{\mathrm{Ob}}\nolimits (\mathcal{S}') = \mathop{\mathrm{Ob}}\nolimits (\mathcal{S}), and
for x, y \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{S}') the set of morphisms between x and y in \mathcal{S}' is the set of strongly cartesian morphisms between x and y in \mathcal{S}.
Let p' : \mathcal{S}' \to \mathcal{C} be the restriction of p to \mathcal{S}'. Then p' : \mathcal{S}' \to \mathcal{C} is fibred in groupoids.
Proof.
Note that the construction makes sense since by Lemma 4.33.2 the identity morphism of any object of \mathcal{S} is strongly cartesian, and the composition of strongly cartesian morphisms is strongly cartesian. The first lifting property of Definition 4.35.1 follows from the condition that in a fibred category given any morphism f : V \to U and x lying over U there exists a strongly cartesian morphism \varphi : y \to x lying over f. Let us check the second lifting property of Definition 4.35.1 for the category p' : \mathcal{S}' \to \mathcal{C} over \mathcal{C}. To do this we argue as in the discussion following Definition 4.35.1. Thus in Diagram 4.35.1.1 the morphisms \phi , \psi and \gamma are strongly cartesian morphisms of \mathcal{S}. Hence \gamma and \phi \circ \psi are strongly cartesian morphisms of \mathcal{S} lying over the same arrow of \mathcal{C} and having the same target in \mathcal{S}. By the discussion following Definition 4.33.1 this means these two arrows are isomorphic as desired (here we use also that any isomorphism in \mathcal{S} is strongly cartesian, by Lemma 4.33.2 again).
\square
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