Lemma 67.6.3 (03Z3)—The Stacks project

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Table of contents
Part 4: Algebraic Spaces
Chapter 67: Morphisms of Algebraic Spaces
Section 67.6: Open morphisms
Lemma 67.6.3 (cite)

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Lemma 67.6.3. The base change of a universally open morphism of algebraic spaces by any morphism of algebraic spaces is universally open.

Proof. This is immediate from the definition. $\square$

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