Lemma 67.10.3 (042N)—The Stacks project

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Table of contents
Part 4: Algebraic Spaces
Chapter 67: Morphisms of Algebraic Spaces
Section 67.10: Monomorphisms
Lemma 67.10.3 (cite)

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Lemma 67.10.3. A monomorphism of algebraic spaces is separated.

Proof. This is true because an isomorphism is a closed immersion, and Lemma 67.10.2 above. $\square$

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