Lemma 76.3.2. A radicial morphism of algebraic spaces is universally injective.
Proof. Let S be a scheme. Let f : X \to Y be a radicial morphism of algebraic spaces over S. It is clear from the definition that given a morphism \mathop{\mathrm{Spec}}(K) \to Y there is at most one lift of this morphism to a morphism into X. Hence we conclude that f is universally injective by Morphisms of Spaces, Lemma 67.19.2. \square
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