Lemma 66.37.5. A smooth morphism of algebraic spaces is locally of finite presentation.
Proof. Let $X \to Y$ be a smooth morphism of algebraic spaces. By definition this means there exists a diagram as in Lemma 66.22.1 with $h$ smooth and surjective vertical arrow $a$. By Morphisms, Lemma 29.34.8 $h$ is locally of finite presentation. Hence $X \to Y$ is locally of finite presentation by definition. $\square$
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