A geometric point of an algebraic space gives a point of its étale topos.
Lemma 66.19.7. Let S be a scheme. Let X be an algebraic space over S. Let \overline{x} be a geometric point of X. Consider the functor
u : X_{\acute{e}tale}\longrightarrow \textit{Sets}, \quad U \longmapsto |U_{\overline{x}}|
Then u defines a point p of the site X_{\acute{e}tale} (Sites, Definition 7.32.2) and its associated stalk functor \mathcal{F} \mapsto \mathcal{F}_ p (Sites, Equation 7.32.1.1) is the functor \mathcal{F} \mapsto \mathcal{F}_{\overline{x}} defined above.
Proof.
In the proof of Lemma 66.19.5 we have seen that the scheme U_{\overline{x}} is a disjoint union of schemes isomorphic to \overline{x}. Thus we can also think of |U_{\overline{x}}| as the set of geometric points of U lying over \overline{x}, i.e., as the collection of morphisms \overline{u} : \overline{x} \to U fitting into the diagram of Definition 66.19.2. From this it follows that u(X) is a singleton, and that u(U \times _ V W) = u(U) \times _{u(V)} u(W) whenever U \to V and W \to V are morphisms in X_{\acute{e}tale}. And, given a covering \{ U_ i \to U\} _{i \in I} in X_{\acute{e}tale} we see that \coprod u(U_ i) \to u(U) is surjective by Lemma 66.19.5. Hence Sites, Proposition 7.33.3 applies, so p is a point of the site X_{\acute{e}tale}. Finally, the our functor \mathcal{F} \mapsto \mathcal{F}_{\overline{s}} is given by exactly the same colimit as the functor \mathcal{F} \mapsto \mathcal{F}_ p associated to p in Sites, Equation 7.32.1.1 which proves the final assertion.
\square
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