Proof.
We write everything out completely.
Proof of (1). Let f : X \to Y be a morphism of schemes. Let \{ X_ i \to X\} _{i \in I} be an étale covering of X. If each composition h_ i : X_ i \to Y has \mathcal{P}, then for each x \in X we can find an i \in I and a point x_ i \in X_ i mapping to x. Then (X_ i, x_ i) \to (X, x) is an étale morphism of germs, and \text{id}_ Y : Y \to Y is an étale morphism, and h_ i is as in part (3) of Definition 35.32.3. Thus we see that f has \mathcal{P}. Conversely, if f has \mathcal{P} then each X_ i \to Y has \mathcal{P} by Definition 35.32.3 part (1).
Proof of (2). Let f : X \to Y be a morphism of schemes. Let \{ Y_ i \to Y\} _{i \in I} be an étale covering of Y. Write X_ i = Y_ i \times _ Y X and h_ i : X_ i \to Y_ i for the base change of f. If each h_ i : X_ i \to Y_ i has \mathcal{P}, then for each x \in X we pick an i \in I and a point x_ i \in X_ i mapping to x. Then (X_ i, x_ i) \to (X, x) is an étale morphism of germs, Y_ i \to Y is étale, and h_ i is as in part (3) of Definition 35.32.3. Thus we see that f has \mathcal{P}. Conversely, if f has \mathcal{P}, then each X_ i \to Y_ i has \mathcal{P} by Definition 35.32.3 part (2).
Proof of (3). Assume f : X \to Y has \mathcal{P} and g : Y \to Z is étale. For every x \in X we can think of (X, x) \to (X, x) as an étale morphism of germs, Y \to Z is an étale morphism, and h = f is as in part (3) of Definition 35.32.3. Thus we see that g \circ f has \mathcal{P}.
Proof of (4). Let f : X \to Y be a morphism and g : Y \to Z étale such that g \circ f has \mathcal{P}. Then by Definition 35.32.3 part (2) we see that \text{pr}_ Y : Y \times _ Z X \to Y has \mathcal{P}. But the morphism (f, 1) : X \to Y \times _ Z X is étale as a section to the étale projection \text{pr}_ X : Y \times _ Z X \to X, see Morphisms, Lemma 29.36.18. Hence f = \text{pr}_ Y \circ (f, 1) has \mathcal{P} by Definition 35.32.3 part (1).
\square
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