Lemma 101.3.6. Let f : \mathcal{X} \to \mathcal{Y} be a morphism of algebraic stacks representable by algebraic spaces. Then the following are equivalent
f is quasi-separated,
\Delta _ f is quasi-compact, or
\Delta _ f is of finite type.
Lemma 101.3.6. Let f : \mathcal{X} \to \mathcal{Y} be a morphism of algebraic stacks representable by algebraic spaces. Then the following are equivalent
f is quasi-separated,
\Delta _ f is quasi-compact, or
\Delta _ f is of finite type.
Proof. The statements “f is quasi-separated”, “\Delta _ f is quasi-compact”, and “\Delta _ f is of finite type” refer to the notions defined in Properties of Stacks, Section 100.3. Note that (2) and (3) are equivalent in view of the fact that \Delta _ f is locally of finite type by Lemma 101.3.4 (and Algebraic Stacks, Lemma 94.10.9). Choose a scheme V and a surjective smooth morphism V \to \mathcal{Y}. Set U = \mathcal{X} \times _\mathcal {Y} V which is an algebraic space by assumption, and the morphism U \to \mathcal{X} is surjective and smooth. By Categories, Lemma 4.31.14 and Properties of Stacks, Lemma 100.3.3 we see that we have: \Delta _ f is quasi-compact if and only if \Delta _{U/V} : U \to U \times _ V U is quasi-compact. If (1) holds, then U \to V is quasi-separated and we see that \Delta _{U/V} is quasi-compact, i.e., (2) holds. Assume (2) holds. Let T be a scheme, and a : T \to \mathcal{Y} a morphism. Set T' = \mathcal{X} \times _\mathcal {Y} T. To prove (1) we have to show that the morphism of algebraic spaces T' \to T is quasi-separated. Using Categories, Lemma 4.31.14 once more we see that \Delta _{T'/T} is the base change of \Delta _ f. Hence our assumption (2) implies that \Delta _{T'/T} is quasi-compact, hence T' \to T is quasi-separated as desired. \square
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