Lemma 37.27.6. Let f : X \to Y be a morphism of schemes. Let n_{X/Y} be the function on Y counting the numbers of geometrically irreducible components of fibres of f introduced in Lemma 37.27.3. Assume f of finite type. Let y \in Y be a point. Then there exists a nonempty open V \subset \overline{\{ y\} } such that n_{X/Y}|_ V is constant.
Proof. Let Z be the reduced induced scheme structure on \overline{\{ y\} }. Let f_ Z : X_ Z \to Z be the base change of f. Clearly it suffices to prove the lemma for f_ Z and the generic point of Z. Hence we may assume that Y is an integral scheme, see Properties, Lemma 28.3.4. Our goal in this case is to produce a nonempty open V \subset Y such that n_{X/Y}|_ V is constant.
We apply Lemma 37.24.8 to f : X \to Y and we get g : Y' \to V \subset Y. As g : Y' \to V is surjective finite étale, in particular open (see Morphisms, Lemma 29.36.13), it suffices to prove that there exists an open V' \subset Y' such that n_{X'/Y'}|_{V'} is constant, see Lemma 37.27.3. Thus we see that we may assume that all irreducible components of the generic fibre X_\eta are geometrically irreducible over \kappa (\eta ).
At this point suppose that X_\eta = X_{1, \eta } \bigcup \ldots \bigcup X_{n, \eta } is the decomposition of the generic fibre into (geometrically) irreducible components. In particular n_{X/Y}(\eta ) = n. Let X_ i be the closure of X_{i, \eta } in X. After shrinking Y we may assume that X = \bigcup X_ i, see Lemma 37.24.5. After shrinking Y some more we see that each fibre of f has at least n irreducible components, see Lemma 37.27.1. Hence n_{X/Y}(y) \geq n for all y \in Y. After shrinking Y some more we obtain that X_{i, y} is geometrically irreducible for each i and all y \in Y, see Lemma 37.27.5. Since X_ y = \bigcup X_{i, y} this shows that n_{X/Y}(y) \leq n and finishes the proof. \square
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