Lemma 97.12.3. In the situation of Lemma 97.12.1 assume
\mathcal{Y}' = \mathcal{Y} and H = \text{id}_\mathcal {Y},
G is representable by algebraic spaces and étale.
Then \mathcal{H}_ d(\mathcal{X}'/\mathcal{Y}) \to \mathcal{H}_ d(\mathcal{X}/\mathcal{Y}) is representable by algebraic spaces and étale. If G is also surjective, then \mathcal{H}_ d(\mathcal{X}'/\mathcal{Y}) \to \mathcal{H}_ d(\mathcal{X}/\mathcal{Y}) is surjective.
Proof.
Let U be a scheme and let \xi = (U, Z, y, x, \alpha ) be an object of \mathcal{H}_ d(\mathcal{X}/\mathcal{Y}) over U. We have to prove that the 2-fibre product
97.12.3.1
\begin{equation} \label{criteria-equation-to-show} (\mathit{Sch}/U)_{fppf} \times _{\xi , \mathcal{H}_ d(\mathcal{X}/\mathcal{Y})} \mathcal{H}_ d(\mathcal{X}'/\mathcal{Y}) \end{equation}
is representable by an algebraic space étale over U. An object of this over U' corresponds to an object x' in the fibre category of \mathcal{X}' over Z_{U'} such that G(x') \cong x|_{Z_{U'}}. By assumption the 2-fibre product
(\mathit{Sch}/Z)_{fppf} \times _{x, \mathcal{X}} \mathcal{X}'
is representable by an algebraic space W such that the projection W \to Z is étale. Then (97.12.3.1) is representable by the algebraic space F parametrizing sections of W \to Z over U introduced in Lemma 97.9.2. Since F \to U is étale we conclude that \mathcal{H}_ d(\mathcal{X}'/\mathcal{Y}) \to \mathcal{H}_ d(\mathcal{X}/\mathcal{Y}) is representable by algebraic spaces and étale. Finally, if \mathcal{X}' \to \mathcal{X} is surjective also, then W \to Z is surjective, and hence F \to U is surjective by Lemma 97.9.1. Thus in this case \mathcal{H}_ d(\mathcal{X}'/\mathcal{Y}) \to \mathcal{H}_ d(\mathcal{X}/\mathcal{Y}) is also surjective.
\square
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