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The Stacks project

Lemma 15.59.7. Let $R$ be a ring. Let $P^\bullet $ be a bounded above complex of flat $R$-modules. Then $P^\bullet $ is K-flat.

Proof. Let $L^\bullet $ be an acyclic complex of $R$-modules. Let $\xi \in H^ n(\text{Tot}(L^\bullet \otimes _ R P^\bullet ))$. We have to show that $\xi = 0$. Since $\text{Tot}^ n(L^\bullet \otimes _ R P^\bullet )$ is a direct sum with terms $L^ a \otimes _ R P^ b$ we see that $\xi $ comes from an element in $H^ n(\text{Tot}(\tau _{\leq m}L^\bullet \otimes _ R P^\bullet ))$ for some $m \in \mathbf{Z}$. Since $\tau _{\leq m}L^\bullet $ is also acyclic we may replace $L^\bullet $ by $\tau _{\leq m}L^\bullet $. Hence we may assume that $L^\bullet $ is bounded above. In this case the spectral sequence of Homology, Lemma 12.25.3 has

\[ {}'E_1^{p, q} = H^ p(L^\bullet \otimes _ R P^ q) \]

which is zero as $P^ q$ is flat and $L^\bullet $ acyclic. Hence $H^*(\text{Tot}(L^\bullet \otimes _ R P^\bullet )) = 0$. $\square$


Comments (2)

Comment #10006 by on

Alternative proof: firstly, one shows a bounded complex of flat modules is K-flat: by induction on , where . For it is clear. The induction step follows by applying the base case and the induction hypothesis to the distinguished triangle induced from the termwise split s.e.s. where (use Lemma 20.26.6).

Next, let be a bounded above complex of flat modules. Then is a direct limit of K-flat complexes and thus K-flat (Lemma 15.59.8).

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  • 4 comment(s) on Section 15.59: Derived tensor product

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