Lemma 15.64.11. Let A \to B be a ring map. Assume that B is pseudo-coherent as an A-module. Let K^\bullet be a complex of B-modules. The following are equivalent
K^\bullet is m-pseudo-coherent as a complex of B-modules, and
K^\bullet is m-pseudo-coherent as a complex of A-modules.
The same equivalence holds for pseudo-coherence.
Proof.
Assume (1). Choose a bounded complex of finite free B-modules E^\bullet and a map \alpha : E^\bullet \to K^\bullet which is an isomorphism on cohomology in degrees > m and a surjection in degree m. Consider the distinguished triangle (E^\bullet , K^\bullet , C(\alpha )^\bullet ). By Lemma 15.64.7 C(\alpha )^\bullet is m-pseudo-coherent as a complex of A-modules. Hence it suffices to prove that E^\bullet is pseudo-coherent as a complex of A-modules, which follows from Lemma 15.64.9. The pseudo-coherent case of (1) \Rightarrow (2) follows from this and Lemma 15.64.5.
Assume (2). Let n be the largest integer such that H^ n(K^\bullet ) \not= 0. We will prove that K^\bullet is m-pseudo-coherent as a complex of B-modules by induction on n - m. The case n < m follows from Lemma 15.64.7. Choose a bounded complex of finite free A-modules E^\bullet and a map \alpha : E^\bullet \to K^\bullet which is an isomorphism on cohomology in degrees > m and a surjection in degree m. Consider the induced map of complexes
\alpha \otimes 1 : E^\bullet \otimes _ A B \to K^\bullet .
Note that C(\alpha \otimes 1)^\bullet is acyclic in degrees \geq n as H^ n(E) \to H^ n(E^\bullet \otimes _ A B) \to H^ n(K^\bullet ) is surjective by construction and since H^ i(E^\bullet \otimes _ A B) = 0 for i > n by the spectral sequence of Example 15.62.4. On the other hand, C(\alpha \otimes 1)^\bullet is m-pseudo-coherent as a complex of A-modules because both K^\bullet and E^\bullet \otimes _ A B (see Lemma 15.64.9) are so, see Lemma 15.64.2. Hence by induction we see that C(\alpha \otimes 1)^\bullet is m-pseudo-coherent as a complex of B-modules. Finally another application of Lemma 15.64.2 shows that K^\bullet is m-pseudo-coherent as a complex of B-modules (as clearly E^\bullet \otimes _ A B is pseudo-coherent as a complex of B-modules). The pseudo-coherent case of (2) \Rightarrow (1) follows from this and Lemma 15.64.5.
\square
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