Lemma 37.62.8. Let f : X \to S be a morphism of schemes. The following are equivalent
f is flat and a local complete intersection morphism, and
f is syntomic.
A morphism is flat and lci if and only if it is syntomic.
Lemma 37.62.8. Let f : X \to S be a morphism of schemes. The following are equivalent
f is flat and a local complete intersection morphism, and
f is syntomic.
Proof. Working affine locally this is More on Algebra, Lemma 15.33.5. We also give a more geometric proof.
Assume (2). By Morphisms, Lemma 29.30.10 for every point x of X there exist affine open neighbourhoods U of x and V of f(x) such that f|_ U : U \to V is standard syntomic. This means that U = \mathop{\mathrm{Spec}}(R[x_1, \ldots , x_ n]/(f_1, \ldots , f_ c)) \to V = \mathop{\mathrm{Spec}}(R) where R[x_1, \ldots , x_ n]/(f_1, \ldots , f_ c) is a relative global complete intersection over R. By Algebra, Lemma 10.136.12 the sequence f_1, \ldots , f_ c is a regular sequence in each local ring R[x_1, \ldots , x_ n]_{\mathfrak q} for every prime \mathfrak q \supset (f_1, \ldots , f_ c). Consider the Koszul complex K_\bullet = K_\bullet (R[x_1, \ldots , x_ n], f_1, \ldots , f_ c) with homology groups H_ i = H_ i(K_\bullet ). By More on Algebra, Lemma 15.30.2 we see that (H_ i)_{\mathfrak q} = 0, i > 0 for every \mathfrak q as above. On the other hand, by More on Algebra, Lemma 15.28.6 we see that H_ i is annihilated by (f_1, \ldots , f_ c). Hence we see that H_ i = 0, i > 0 and f_1, \ldots , f_ c is a Koszul-regular sequence. This proves that U \to V factors as a Koszul-regular immersion U \to \mathbf{A}^ n_ V followed by a smooth morphism as desired.
Assume (1). Then f is a flat and locally of finite presentation (Lemma 37.62.4). Hence, according to Morphisms, Lemma 29.30.10 it suffices to show that the local rings \mathcal{O}_{X_ s, x} are local complete intersection rings. Choose, locally on X, a factorization f = \pi \circ i for some Koszul-regular immersion i : X \to P and smooth morphism \pi : P \to S. Note that X \to P is a relative quasi-regular immersion over S, see Divisors, Definition 31.22.2. Hence according to Divisors, Lemma 31.22.4 we see that X \to P is a regular immersion and the same remains true after any base change. Thus each fibre is a regular immersion, whence all the local rings of all the fibres of X are local complete intersections. \square
Comments (1)
Comment #825 by Johan Commelin on
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