Definition 76.47.1. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S.
We say f is perfect if the equivalent conditions of Morphisms of Spaces, Lemma 67.22.1 hold with \mathcal{P} =“perfect”.
Let x \in |X|. We say f is perfect at x if there exists an open neighbourhood X' \subset X of x such that f|_{X'} : X' \to Y is perfect.
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