Lemma 72.10.9. Let k be a field. Let f : X \to Y be a monomorphism of algebraic spaces over k. If Y is locally quasi-finite over k so is X.
Proof. Assume Y is locally quasi-finite over k. By Lemma 72.10.8 we see that Y = \coprod \mathop{\mathrm{Spec}}(A_ i) where each A_ i is an Artinian local ring finite over k. By Decent Spaces, Lemma 68.19.1 we see that X is a scheme. Consider X_ i = f^{-1}(\mathop{\mathrm{Spec}}(A_ i)). Then X_ i has either one or zero points. If X_ i has zero points there is nothing to prove. If X_ i has one point, then X_ i = \mathop{\mathrm{Spec}}(B_ i) with B_ i a zero dimensional local ring and A_ i \to B_ i is an epimorphism of rings. In particular A_ i/\mathfrak m_{A_ i} = B_ i/\mathfrak m_{A_ i}B_ i and we see that A_ i \to B_ i is surjective by Nakayama's lemma, Algebra, Lemma 10.20.1 (because \mathfrak m_{A_ i} is a nilpotent ideal!). Thus B_ i is a finite local k-algebra, and we conclude by Lemma 72.10.8 that X \to \mathop{\mathrm{Spec}}(k) is locally quasi-finite. \square
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