Proof. By Lemma 16.8.4 it suffices to prove this for $k \to \Lambda$ where $\Lambda$ is Noetherian and geometrically regular over $k$. Let $k \to A \to \Lambda$ be a factorization with $A$ a finite type $k$-algebra. It suffices to construct a factorization $A \to B \to \Lambda$ with $B$ of finite type such that $\mathfrak h_ B = \Lambda$, see Lemma 16.2.8. Hence we may perform Noetherian induction on the ideal $\mathfrak h_ A$. Pick a prime $\mathfrak q \supset \mathfrak h_ A$ such that $\mathfrak q$ is minimal over $\mathfrak h_ A$. It now suffices to resolve $k \to A \to \Lambda \supset \mathfrak q$ (as defined in the text following Situation 16.9.1). If the characteristic of $k$ is zero, this follows from Lemma 16.10.3. If the characteristic of $k$ is $p > 0$, this follows from Lemma 16.11.4. $\square$

There are also:

• 3 comment(s) on Section 16.12: The main theorem

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).